20p^2=1000-20p

Solution for 20p^2=1000-20p equation:

20p^2=1000-20p

We move all terms to the left:

20p^2-(1000-20p)=0

We add all the numbers together, and all the variables

20p^2-(-20p+1000)=0

We get rid of parentheses

20p^2+20p-1000=0

a = 20; b = 20; c = -1000;
Δ = b2-4ac
Δ = 202-4·20·(-1000)
Δ = 80400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80400}=\sqrt{400*201}=\sqrt{400}*\sqrt{201}=20\sqrt{201}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20\sqrt{201}}{2*20}=\frac{-20-20\sqrt{201}}{40}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20\sqrt{201}}{2*20}=\frac{-20+20\sqrt{201}}{40}
$